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karishma koshy on 14 Jul 2019
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Edited: karishma koshy on 15 Jul 2019
Accepted Answer: Adam Danz
- DataTable_SER.xlsx
I have a table with two columns as circle's centre position and third one with frame number 1-1000. I want to obtain the values of circle centres in frame n and n-1 at a time, inorder to make matrix out of it
How can I do that?
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Accepted Answer
Adam Danz on 14 Jul 2019
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Edited: Adam Danz on 14 Jul 2019
I'm not sure what you mean by "in order to make a matrix out of it". If this demo doesn't address the problem, please provide an example. Otherwise, here's how to extract the (x,y) coordinates for a given frame.
%Fake data
T = table((1:9)',(2:10)',[1;1;1;2;2;2;3;3;3],'VariableNames',{'X','Y','Frame'});
f = 2; % frame number
frameIdx = T.Frame == f; %row numbers of frame n
frameIdx = T.Frame == f-1; %row numbers of frame n-1 (not used in this demo)
% FROM HERE YOU CAN DO LOTS OF THINGS LIKE...
% ...isolate rows of table that belong to frame n
T(frameIdx,:)
% ...isolate only the (X,Y) values that belong to frame n
T(frameIdx,{'X','Y'})
% ...put (X,Y) values from frame n into a matrix
T{frameIdx,{'X','Y'}}
I recommend keeping the data in the table rather than extracting it into a matrix unless your analysis requres a matrix.
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karishma koshy on 14 Jul 2019
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Im actually trying to do munkres Hungarian algorithm. So I want to find the position difference of a particular circle from one frame to another frame. The circle represents the bacteria, and it's actually moving.
How can I find the distance between points.
Adam Danz on 14 Jul 2019
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Edited: Adam Danz on 15 Jul 2019
"How can I find the distance between points."
Distance = sqrt((x2-x1)^2 + (y2-y1)^2)
Thanks to Pythagoras.
(x1,y1) are the coordinates at frame n; (x2,y2) are coordinates at frame n-1 (or the other way around; it doesn't matter).
karishma koshy on 14 Jul 2019
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Dear sir
Can you help me construct a for loop to find the distance between loops in n and n-1 frames and terminate the loop when it's reached the last value of both the frames
Adam Danz on 15 Jul 2019
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The loop will probably look something like this; T is your table.
% Create fake data
T = table((1:9)',(2:10)',[1;1;1;2;2;2;3;3;3],'VariableNames',{'X','Y','Frame'});
n = size(T,1)'; %number of rows in your table
distFcn = @(x1,x2,y1,y2)sqrt((x2-x1)^2 + (y2-y1)^2); %distance function
% Loop through each row starting at row #2
d = zeros(n-1,1); %create a vector where the distances will be stored
for i = 2:n
d(i-1) = distFcn(T.X(i-1),T.X(i),T.Y(i-1),T.Y(i));
end
And you can do that without a loop, too.
distFcn = @(x1,x2,y1,y2)sqrt((x2-x1).^2 + (y2-y1).^2); %distance function
% ^ ^ note the dots
d = distFcn(T.X(2:end),T.X(1:end-1),T.Y(2:end),T.Y(1:end-1))
karishma koshy on 15 Jul 2019
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Edited: karishma koshy on 15 Jul 2019
Dear Sir I'm aiming to measure the distance between all points in one frame and all points in the next frame. So I want to
Create a table (let’s call this “table i”)which only contains points in frame i (where “i" is the index of that frame) Create another table (“table i+1”), which only contains points in frame i+1 Create a 2D distance matrix (width equal to the number of points in frame i and height equal to the number of points in frame i+1) where each element is the Pythagoras distance between two points.
How can I implement this as a code ? Thank you
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